8(2y-3)-2=8(y-3)+2y-2

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Solution for 8(2y-3)-2=8(y-3)+2y-2 equation: 



8(2y-3)-2=8(y-3)+2y-2

We move all terms to the left:

8(2y-3)-2-(8(y-3)+2y-2)=0

We multiply parentheses

16y-(8(y-3)+2y-2)-24-2=0



We calculate terms in parentheses: -(8(y-3)+2y-2), so:

8(y-3)+2y-2

We add all the numbers together, and all the variables

2y+8(y-3)-2

We multiply parentheses

2y+8y-24-2

We add all the numbers together, and all the variables

10y-26

Back to the equation:

-(10y-26)



We add all the numbers together, and all the variables

16y-(10y-26)-26=0

We get rid of parentheses

16y-10y+26-26=0

We add all the numbers together, and all the variables

6y=0

y=0/6

y=0

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