8(2y+1)=3(7y-4)

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Solution for 8(2y+1)=3(7y-4) equation:


Simplifying
8(2y + 1) = 3(7y + -4)

Reorder the terms:
8(1 + 2y) = 3(7y + -4)
(1 * 8 + 2y * 8) = 3(7y + -4)
(8 + 16y) = 3(7y + -4)

Reorder the terms:
8 + 16y = 3(-4 + 7y)
8 + 16y = (-4 * 3 + 7y * 3)
8 + 16y = (-12 + 21y)

Solving
8 + 16y = -12 + 21y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-21y' to each side of the equation.
8 + 16y + -21y = -12 + 21y + -21y

Combine like terms: 16y + -21y = -5y
8 + -5y = -12 + 21y + -21y

Combine like terms: 21y + -21y = 0
8 + -5y = -12 + 0
8 + -5y = -12

Add '-8' to each side of the equation.
8 + -8 + -5y = -12 + -8

Combine like terms: 8 + -8 = 0
0 + -5y = -12 + -8
-5y = -12 + -8

Combine like terms: -12 + -8 = -20
-5y = -20

Divide each side by '-5'.
y = 4

Simplifying
y = 4

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