8(2x-7)=4x+8

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Solution for 8(2x-7)=4x+8 equation: 



8(2x-7)=4x+8

We move all terms to the left:

8(2x-7)-(4x+8)=0

We multiply parentheses

16x-(4x+8)-56=0

We get rid of parentheses

16x-4x-8-56=0

We add all the numbers together, and all the variables

12x-64=0

We move all terms containing x to the left, all other terms to the right

12x=64

x=64/12

x=5+1/3

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