8(2x-4)=4(-4x+8)

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Solution for 8(2x-4)=4(-4x+8) equation: 



8(2x-4)=4(-4x+8)

We move all terms to the left:

8(2x-4)-(4(-4x+8))=0

We multiply parentheses

16x-(4(-4x+8))-32=0



We calculate terms in parentheses: -(4(-4x+8)), so:

4(-4x+8)

We multiply parentheses

-16x+32

Back to the equation:

-(-16x+32)



We get rid of parentheses

16x+16x-32-32=0

We add all the numbers together, and all the variables

32x-64=0

We move all terms containing x to the left, all other terms to the right

32x=64

x=64/32

x=2

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