8(2x-3)=2(x-19)

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Solution for 8(2x-3)=2(x-19) equation: 



8(2x-3)=2(x-19)

We move all terms to the left:

8(2x-3)-(2(x-19))=0

We multiply parentheses

16x-(2(x-19))-24=0



We calculate terms in parentheses: -(2(x-19)), so:

2(x-19)

We multiply parentheses

2x-38

Back to the equation:

-(2x-38)



We get rid of parentheses

16x-2x+38-24=0

We add all the numbers together, and all the variables

14x+14=0

We move all terms containing x to the left, all other terms to the right

14x=-14

x=-14/14

x=-1

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