8(2x-3)=10x+6(x-4)

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Solution for 8(2x-3)=10x+6(x-4) equation:



8(2x-3)=10x+6(x-4)
We move all terms to the left:
8(2x-3)-(10x+6(x-4))=0
We multiply parentheses
16x-(10x+6(x-4))-24=0
We calculate terms in parentheses: -(10x+6(x-4)), so:
10x+6(x-4)
We multiply parentheses
10x+6x-24
We add all the numbers together, and all the variables
16x-24
Back to the equation:
-(16x-24)
We get rid of parentheses
16x-16x+24-24=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0

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