8(2x-3)-5(3x-4)=10

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Solution for 8(2x-3)-5(3x-4)=10 equation:


Simplifying
8(2x + -3) + -5(3x + -4) = 10

Reorder the terms:
8(-3 + 2x) + -5(3x + -4) = 10
(-3 * 8 + 2x * 8) + -5(3x + -4) = 10
(-24 + 16x) + -5(3x + -4) = 10

Reorder the terms:
-24 + 16x + -5(-4 + 3x) = 10
-24 + 16x + (-4 * -5 + 3x * -5) = 10
-24 + 16x + (20 + -15x) = 10

Reorder the terms:
-24 + 20 + 16x + -15x = 10

Combine like terms: -24 + 20 = -4
-4 + 16x + -15x = 10

Combine like terms: 16x + -15x = 1x
-4 + 1x = 10

Solving
-4 + 1x = 10

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 1x = 10 + 4

Combine like terms: -4 + 4 = 0
0 + 1x = 10 + 4
1x = 10 + 4

Combine like terms: 10 + 4 = 14
1x = 14

Divide each side by '1'.
x = 14

Simplifying
x = 14

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