8(2x-10)=4(-20+4x)

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Solution for 8(2x-10)=4(-20+4x) equation: 



8(2x-10)=4(-20+4x)

We move all terms to the left:

8(2x-10)-(4(-20+4x))=0

We add all the numbers together, and all the variables

8(2x-10)-(4(4x-20))=0

We multiply parentheses

16x-(4(4x-20))-80=0



We calculate terms in parentheses: -(4(4x-20)), so:

4(4x-20)

We multiply parentheses

16x-80

Back to the equation:

-(16x-80)



We get rid of parentheses

16x-16x+80-80=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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