8(2x-10)=32

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Solution for 8(2x-10)=32 equation: 



8(2x-10)=32

We move all terms to the left:

8(2x-10)-(32)=0

We multiply parentheses

16x-80-32=0

We add all the numbers together, and all the variables

16x-112=0

We move all terms containing x to the left, all other terms to the right

16x=112

x=112/16

x=7

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