8(2x+4x+1)=56

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Solution for 8(2x+4x+1)=56 equation: 



8(2x+4x+1)=56

We move all terms to the left:

8(2x+4x+1)-(56)=0

We add all the numbers together, and all the variables

8(6x+1)-56=0

We multiply parentheses

48x+8-56=0

We add all the numbers together, and all the variables

48x-48=0

We move all terms containing x to the left, all other terms to the right

48x=48

x=48/48

x=1

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