8(2x+4)-21=4(4x+1)+7

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Solution for 8(2x+4)-21=4(4x+1)+7 equation: 



8(2x+4)-21=4(4x+1)+7

We move all terms to the left:

8(2x+4)-21-(4(4x+1)+7)=0

We multiply parentheses

16x-(4(4x+1)+7)+32-21=0



We calculate terms in parentheses: -(4(4x+1)+7), so:

4(4x+1)+7

We multiply parentheses

16x+4+7

We add all the numbers together, and all the variables

16x+11

Back to the equation:

-(16x+11)



We add all the numbers together, and all the variables

16x-(16x+11)+11=0

We get rid of parentheses

16x-16x-11+11=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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