8(2x+2)-5=4(4x+4)-5

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Solution for 8(2x+2)-5=4(4x+4)-5 equation: 


Simplifying
8(2x + 2) + -5 = 4(4x + 4) + -5

Reorder the terms:
8(2 + 2x) + -5 = 4(4x + 4) + -5
(2 * 8 + 2x * 8) + -5 = 4(4x + 4) + -5
(16 + 16x) + -5 = 4(4x + 4) + -5

Reorder the terms:
16 + -5 + 16x = 4(4x + 4) + -5

Combine like terms: 16 + -5 = 11
11 + 16x = 4(4x + 4) + -5

Reorder the terms:
11 + 16x = 4(4 + 4x) + -5
11 + 16x = (4 * 4 + 4x * 4) + -5
11 + 16x = (16 + 16x) + -5

Reorder the terms:
11 + 16x = 16 + -5 + 16x

Combine like terms: 16 + -5 = 11
11 + 16x = 11 + 16x

Add '-11' to each side of the equation.
11 + -11 + 16x = 11 + -11 + 16x

Combine like terms: 11 + -11 = 0
0 + 16x = 11 + -11 + 16x
16x = 11 + -11 + 16x

Combine like terms: 11 + -11 = 0
16x = 0 + 16x
16x = 16x

Add '-16x' to each side of the equation.
16x + -16x = 16x + -16x

Combine like terms: 16x + -16x = 0
0 = 16x + -16x

Combine like terms: 16x + -16x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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