8(2x+2)-3x=6(-3x-4)

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Solution for 8(2x+2)-3x=6(-3x-4) equation: 



8(2x+2)-3x=6(-3x-4)

We move all terms to the left:

8(2x+2)-3x-(6(-3x-4))=0

We add all the numbers together, and all the variables

-3x+8(2x+2)-(6(-3x-4))=0

We multiply parentheses

-3x+16x-(6(-3x-4))+16=0



We calculate terms in parentheses: -(6(-3x-4)), so:

6(-3x-4)

We multiply parentheses

-18x-24

Back to the equation:

-(-18x-24)



We add all the numbers together, and all the variables

13x-(-18x-24)+16=0

We get rid of parentheses

13x+18x+24+16=0

We add all the numbers together, and all the variables

31x+40=0

We move all terms containing x to the left, all other terms to the right

31x=-40

x=-40/31

x=-1+9/31

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