8(2x+1)-5(x-4)=

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Solution for 8(2x+1)-5(x-4)= equation:


Simplifying
8(2x + 1) + -5(x + -4) = 0

Reorder the terms:
8(1 + 2x) + -5(x + -4) = 0
(1 * 8 + 2x * 8) + -5(x + -4) = 0
(8 + 16x) + -5(x + -4) = 0

Reorder the terms:
8 + 16x + -5(-4 + x) = 0
8 + 16x + (-4 * -5 + x * -5) = 0
8 + 16x + (20 + -5x) = 0

Reorder the terms:
8 + 20 + 16x + -5x = 0

Combine like terms: 8 + 20 = 28
28 + 16x + -5x = 0

Combine like terms: 16x + -5x = 11x
28 + 11x = 0

Solving
28 + 11x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-28' to each side of the equation.
28 + -28 + 11x = 0 + -28

Combine like terms: 28 + -28 = 0
0 + 11x = 0 + -28
11x = 0 + -28

Combine like terms: 0 + -28 = -28
11x = -28

Divide each side by '11'.
x = -2.545454545

Simplifying
x = -2.545454545

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