8(2v+1)=4(2v+2)

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Solution for 8(2v+1)=4(2v+2) equation:


Simplifying
8(2v + 1) = 4(2v + 2)

Reorder the terms:
8(1 + 2v) = 4(2v + 2)
(1 * 8 + 2v * 8) = 4(2v + 2)
(8 + 16v) = 4(2v + 2)

Reorder the terms:
8 + 16v = 4(2 + 2v)
8 + 16v = (2 * 4 + 2v * 4)
8 + 16v = (8 + 8v)

Add '-8' to each side of the equation.
8 + -8 + 16v = 8 + -8 + 8v

Combine like terms: 8 + -8 = 0
0 + 16v = 8 + -8 + 8v
16v = 8 + -8 + 8v

Combine like terms: 8 + -8 = 0
16v = 0 + 8v
16v = 8v

Solving
16v = 8v

Solving for variable 'v'.

Move all terms containing v to the left, all other terms to the right.

Add '-8v' to each side of the equation.
16v + -8v = 8v + -8v

Combine like terms: 16v + -8v = 8v
8v = 8v + -8v

Combine like terms: 8v + -8v = 0
8v = 0

Divide each side by '8'.
v = 0

Simplifying
v = 0

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