8(2f+-+2)=7(3f+2)

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Solution for 8(2f+-+2)=7(3f+2) equation: 



8(2f+-+2)=7(3f+2)

We move all terms to the left:

8(2f+-+2)-(7(3f+2))=0

We add all the numbers together, and all the variables

8(+2f)-(7(3f+2))=0

We multiply parentheses

16f-(7(3f+2))=0



We calculate terms in parentheses: -(7(3f+2)), so:

7(3f+2)

We multiply parentheses

21f+14

Back to the equation:

-(21f+14)



We get rid of parentheses

16f-21f-14=0

We add all the numbers together, and all the variables

-5f-14=0

We move all terms containing f to the left, all other terms to the right

-5f=14

f=14/-5

f=-2+4/5

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