8(2b+1)=3(2b-8)-16

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Solution for 8(2b+1)=3(2b-8)-16 equation: 



8(2b+1)=3(2b-8)-16

We move all terms to the left:

8(2b+1)-(3(2b-8)-16)=0

We multiply parentheses

16b-(3(2b-8)-16)+8=0



We calculate terms in parentheses: -(3(2b-8)-16), so:

3(2b-8)-16

We multiply parentheses

6b-24-16

We add all the numbers together, and all the variables

6b-40

Back to the equation:

-(6b-40)



We get rid of parentheses

16b-6b+40+8=0

We add all the numbers together, and all the variables

10b+48=0

We move all terms containing b to the left, all other terms to the right

10b=-48

b=-48/10

b=-4+4/5

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