8(1y+2)=2(3y+4)

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Solution for 8(1y+2)=2(3y+4) equation: 



8(1y+2)=2(3y+4)

We move all terms to the left:

8(1y+2)-(2(3y+4))=0

We add all the numbers together, and all the variables

8(y+2)-(2(3y+4))=0

We multiply parentheses

8y-(2(3y+4))+16=0



We calculate terms in parentheses: -(2(3y+4)), so:

2(3y+4)

We multiply parentheses

6y+8

Back to the equation:

-(6y+8)



We get rid of parentheses

8y-6y-8+16=0

We add all the numbers together, and all the variables

2y+8=0

We move all terms containing y to the left, all other terms to the right

2y=-8

y=-8/2

y=-4

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