8(1q-5)=2(3q-10)

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Solution for 8(1q-5)=2(3q-10) equation:



8(1q-5)=2(3q-10)
We move all terms to the left:
8(1q-5)-(2(3q-10))=0
We add all the numbers together, and all the variables
8(q-5)-(2(3q-10))=0
We multiply parentheses
8q-(2(3q-10))-40=0
We calculate terms in parentheses: -(2(3q-10)), so:
2(3q-10)
We multiply parentheses
6q-20
Back to the equation:
-(6q-20)
We get rid of parentheses
8q-6q+20-40=0
We add all the numbers together, and all the variables
2q-20=0
We move all terms containing q to the left, all other terms to the right
2q=20
q=20/2
q=10

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