8(1k+3)=12k+-4

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Solution for 8(1k+3)=12k+-4 equation: 



8(1k+3)=12k+-4

We move all terms to the left:

8(1k+3)-(12k+-4)=0

We add all the numbers together, and all the variables

8(k+3)-(12k-4)=0

We multiply parentheses

8k-(12k-4)+24=0

We get rid of parentheses

8k-12k+4+24=0

We add all the numbers together, and all the variables

-4k+28=0

We move all terms containing k to the left, all other terms to the right

-4k=-28

k=-28/-4

k=+7

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