8(10-2x)=8x+40

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Solution for 8(10-2x)=8x+40 equation: 



8(10-2x)=8x+40

We move all terms to the left:

8(10-2x)-(8x+40)=0

We add all the numbers together, and all the variables

8(-2x+10)-(8x+40)=0

We multiply parentheses

-16x-(8x+40)+80=0

We get rid of parentheses

-16x-8x-40+80=0

We add all the numbers together, and all the variables

-24x+40=0

We move all terms containing x to the left, all other terms to the right

-24x=-40

x=-40/-24

x=1+2/3

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