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8(1/4x-3)=8(3/8x)
We move all terms to the left:
8(1/4x-3)-(8(3/8x))=0
Domain of the equation: 4x-3)!=0
x∈R
Domain of the equation: 8x))!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
8(1/4x-3)-(8(+3/8x))=0
We multiply parentheses
8x-(8(+3/8x))-24=0
We multiply all the terms by the denominator
8x*8x))-(8(-24*8x))+3=0
Wy multiply elements
64x^2-192x=0
a = 64; b = -192; c = 0;
Δ = b2-4ac
Δ = -1922-4·64·0
Δ = 36864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36864}=192$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-192)-192}{2*64}=\frac{0}{128} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-192)+192}{2*64}=\frac{384}{128} =3 $
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