8(1/2c-2)+1=2(3c+5)-3

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Solution for 8(1/2c-2)+1=2(3c+5)-3 equation: 



8(1/2c-2)+1=2(3c+5)-3

We move all terms to the left:

8(1/2c-2)+1-(2(3c+5)-3)=0



Domain of the equation: 2c-2)!=0

c∈R



We multiply parentheses

8c-(2(3c+5)-3)-16+1=0



We calculate terms in parentheses: -(2(3c+5)-3), so:

2(3c+5)-3

We multiply parentheses

6c+10-3

We add all the numbers together, and all the variables

6c+7

Back to the equation:

-(6c+7)



We add all the numbers together, and all the variables

8c-(6c+7)-15=0

We get rid of parentheses

8c-6c-7-15=0

We add all the numbers together, and all the variables

2c-22=0

We move all terms containing c to the left, all other terms to the right

2c=22

c=22/2

c=11

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