8(1+7x)=-8(2-8x)-6x

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Solution for 8(1+7x)=-8(2-8x)-6x equation: 



8(1+7x)=-8(2-8x)-6x

We move all terms to the left:

8(1+7x)-(-8(2-8x)-6x)=0

We add all the numbers together, and all the variables

8(7x+1)-(-8(-8x+2)-6x)=0

We multiply parentheses

56x-(-8(-8x+2)-6x)+8=0



We calculate terms in parentheses: -(-8(-8x+2)-6x), so:

-8(-8x+2)-6x

We add all the numbers together, and all the variables

-6x-8(-8x+2)

We multiply parentheses

-6x+64x-16

We add all the numbers together, and all the variables

58x-16

Back to the equation:

-(58x-16)



We get rid of parentheses

56x-58x+16+8=0

We add all the numbers together, and all the variables

-2x+24=0

We move all terms containing x to the left, all other terms to the right

-2x=-24

x=-24/-2

x=+12

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