8(1+5x)=-40-8x

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Solution for 8(1+5x)=-40-8x equation: 



8(1+5x)=-40-8x

We move all terms to the left:

8(1+5x)-(-40-8x)=0

We add all the numbers together, and all the variables

8(5x+1)-(-8x-40)=0

We multiply parentheses

40x-(-8x-40)+8=0

We get rid of parentheses

40x+8x+40+8=0

We add all the numbers together, and all the variables

48x+48=0

We move all terms containing x to the left, all other terms to the right

48x=-48

x=-48/48

x=-1

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