8(-3/2x+6)=-9(4/3x)-8

Solution for 8(-3/2x+6)=-9(4/3x)-8 equation:

8(-3/2x+6)=-9(4/3x)-8

We move all terms to the left:

8(-3/2x+6)-(-9(4/3x)-8)=0


Domain of the equation: 2x+6)!=0

x∈R



Domain of the equation: 3x)-8)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

8(-3/2x+6)-(-9(+4/3x)-8)=0

We multiply parentheses

-24x-(-9(+4/3x)-8)+48=0

We multiply all the terms by the denominator


-24x*3x)-8)-(-9(+48*3x)-8)+4=0

Wy multiply elements

-72x^2+144x=0

a = -72; b = 144; c = 0;
Δ = b2-4ac
Δ = 1442-4·(-72)·0
Δ = 20736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{20736}=144$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(144)-144}{2*-72}=\frac{-288}{-144}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(144)+144}{2*-72}=\frac{0}{-144}
=0
$