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8(-1+m)+3=2(m-5)1/2)
We move all terms to the left:
8(-1+m)+3-(2(m-5)1/2))=0
We add all the numbers together, and all the variables
8(m-1)-(2(m-5)1/2))+3=0
We multiply parentheses
8m-(2(m-5)1/2))+3-8=0
We multiply all the terms by the denominator
8m*2))+3-8-(2(m-5)1=0
We add all the numbers together, and all the variables
8m*2))+3-8-(2(m=0
Wy multiply elements
16m^2=0
a = 16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·16·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$m=\frac{-b}{2a}=\frac{0}{32}=0$
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