8(-1+m)+3=(m-51/5)

Solution for 8(-1+m)+3=(m-51/5) equation:

8(-1+m)+3=(m-51/5)

We move all terms to the left:

8(-1+m)+3-((m-51/5))=0

We add all the numbers together, and all the variables

8(m-1)-((+m-51/5))+3=0

We multiply parentheses

8m-((+m-51/5))-8+3=0

We multiply all the terms by the denominator


8m*5))-((+m-51-8*5))+3*5))=0

We add all the numbers together, and all the variables

8m*5))-((m-91))+3*5))=0

We add all the numbers together, and all the variables

8m*5))-((m=0

Wy multiply elements

40m^2=0

a = 40; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·40·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{80}=0$