8((3x/4)+1)=56

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Solution for 8((3x/4)+1)=56 equation: 



8((3x/4)+1)=56

We move all terms to the left:

8((3x/4)+1)-(56)=0

We add all the numbers together, and all the variables

8((+3x/4)+1)-56=0

We multiply all the terms by the denominator


8((+3x-56*4)+1)=0

We add all the numbers together, and all the variables

8((3x-224)+1)=0

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