7z-4=3(4+z)

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Solution for 7z-4=3(4+z) equation: 



7z-4=3(4+z)

We move all terms to the left:

7z-4-(3(4+z))=0

We add all the numbers together, and all the variables

7z-(3(z+4))-4=0



We calculate terms in parentheses: -(3(z+4)), so:

3(z+4)

We multiply parentheses

3z+12

Back to the equation:

-(3z+12)



We get rid of parentheses

7z-3z-12-4=0

We add all the numbers together, and all the variables

4z-16=0

We move all terms containing z to the left, all other terms to the right

4z=16

z=16/4

z=4

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