7z-3=-1+5(7z-2)

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Solution for 7z-3=-1+5(7z-2) equation:



7z-3=-1+5(7z-2)
We move all terms to the left:
7z-3-(-1+5(7z-2))=0
We calculate terms in parentheses: -(-1+5(7z-2)), so:
-1+5(7z-2)
determiningTheFunctionDomain 5(7z-2)-1
We multiply parentheses
35z-10-1
We add all the numbers together, and all the variables
35z-11
Back to the equation:
-(35z-11)
We get rid of parentheses
7z-35z+11-3=0
We add all the numbers together, and all the variables
-28z+8=0
We move all terms containing z to the left, all other terms to the right
-28z=-8
z=-8/-28
z=2/7

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