7z-204=3(4-6z)-2z

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Solution for 7z-204=3(4-6z)-2z equation: 



7z-204=3(4-6z)-2z

We move all terms to the left:

7z-204-(3(4-6z)-2z)=0

We add all the numbers together, and all the variables

7z-(3(-6z+4)-2z)-204=0



We calculate terms in parentheses: -(3(-6z+4)-2z), so:

3(-6z+4)-2z

We add all the numbers together, and all the variables

-2z+3(-6z+4)

We multiply parentheses

-2z-18z+12

We add all the numbers together, and all the variables

-20z+12

Back to the equation:

-(-20z+12)



We get rid of parentheses

7z+20z-12-204=0

We add all the numbers together, and all the variables

27z-216=0

We move all terms containing z to the left, all other terms to the right

27z=216

z=216/27

z=8

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