7z-(6z+8)=24-(z+2)

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Solution for 7z-(6z+8)=24-(z+2) equation: 



7z-(6z+8)=24-(z+2)

We move all terms to the left:

7z-(6z+8)-(24-(z+2))=0

We get rid of parentheses

7z-6z-(24-(z+2))-8=0



We calculate terms in parentheses: -(24-(z+2)), so:

24-(z+2)

determiningTheFunctionDomain
-(z+2)+24

We get rid of parentheses

-z-2+24

We add all the numbers together, and all the variables

-1z+22

Back to the equation:

-(-1z+22)



We add all the numbers together, and all the variables

z-(-1z+22)-8=0

We get rid of parentheses

z+1z-22-8=0

We add all the numbers together, and all the variables

2z-30=0

We move all terms containing z to the left, all other terms to the right

2z=30

z=30/2

z=15

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