7z-(2+z)=2(3z-1)

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Solution for 7z-(2+z)=2(3z-1) equation:


Simplifying
7z + -1(2 + z) = 2(3z + -1)
7z + (2 * -1 + z * -1) = 2(3z + -1)
7z + (-2 + -1z) = 2(3z + -1)

Reorder the terms:
-2 + 7z + -1z = 2(3z + -1)

Combine like terms: 7z + -1z = 6z
-2 + 6z = 2(3z + -1)

Reorder the terms:
-2 + 6z = 2(-1 + 3z)
-2 + 6z = (-1 * 2 + 3z * 2)
-2 + 6z = (-2 + 6z)

Add '2' to each side of the equation.
-2 + 2 + 6z = -2 + 2 + 6z

Combine like terms: -2 + 2 = 0
0 + 6z = -2 + 2 + 6z
6z = -2 + 2 + 6z

Combine like terms: -2 + 2 = 0
6z = 0 + 6z
6z = 6z

Add '-6z' to each side of the equation.
6z + -6z = 6z + -6z

Combine like terms: 6z + -6z = 0
0 = 6z + -6z

Combine like terms: 6z + -6z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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