7z+5z+2z+2=33

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Solution for 7z+5z+2z+2=33 equation:



7z+5z+2z+2=33
We move all terms to the left:
7z+5z+2z+2-(33)=0
We add all the numbers together, and all the variables
14z-31=0
We move all terms containing z to the left, all other terms to the right
14z=31
z=31/14
z=2+3/14

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