7z+4z=31+3z+17

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Solution for 7z+4z=31+3z+17 equation: 



7z+4z=31+3z+17

We move all terms to the left:

7z+4z-(31+3z+17)=0

We add all the numbers together, and all the variables

7z+4z-(3z+48)=0

We add all the numbers together, and all the variables

11z-(3z+48)=0

We get rid of parentheses

11z-3z-48=0

We add all the numbers together, and all the variables

8z-48=0

We move all terms containing z to the left, all other terms to the right

8z=48

z=48/8

z=6

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