7z+27=5(z+25)

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Solution for 7z+27=5(z+25) equation: 



7z+27=5(z+25)

We move all terms to the left:

7z+27-(5(z+25))=0



We calculate terms in parentheses: -(5(z+25)), so:

5(z+25)

We multiply parentheses

5z+125

Back to the equation:

-(5z+125)



We get rid of parentheses

7z-5z-125+27=0

We add all the numbers together, and all the variables

2z-98=0

We move all terms containing z to the left, all other terms to the right

2z=98

z=98/2

z=49

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