7z+(5z-4)=14

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Solution for 7z+(5z-4)=14 equation: 



7z+(5z-4)=14

We move all terms to the left:

7z+(5z-4)-(14)=0

We get rid of parentheses

7z+5z-4-14=0

We add all the numbers together, and all the variables

12z-18=0

We move all terms containing z to the left, all other terms to the right

12z=18

z=18/12

z=1+1/2

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