7y2-22y-16=0

Solution for 7y2-22y-16=0 equation:

7y^2-22y-16=0

a = 7; b = -22; c = -16;
Δ = b2-4ac
Δ = -222-4·7·(-16)
Δ = 932
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{932}=\sqrt{4*233}=\sqrt{4}*\sqrt{233}=2\sqrt{233}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-2\sqrt{233}}{2*7}=\frac{22-2\sqrt{233}}{14}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+2\sqrt{233}}{2*7}=\frac{22+2\sqrt{233}}{14}
$