7y-y=2(y-4)+1

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Solution for 7y-y=2(y-4)+1 equation: 



7y-y=2(y-4)+1

We move all terms to the left:

7y-y-(2(y-4)+1)=0

We add all the numbers together, and all the variables

6y-(2(y-4)+1)=0



We calculate terms in parentheses: -(2(y-4)+1), so:

2(y-4)+1

We multiply parentheses

2y-8+1

We add all the numbers together, and all the variables

2y-7

Back to the equation:

-(2y-7)



We get rid of parentheses

6y-2y+7=0

We add all the numbers together, and all the variables

4y+7=0

We move all terms containing y to the left, all other terms to the right

4y=-7

y=-7/4

y=-1+3/4

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