7y-7=3(2+2y)-4y+7

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Solution for 7y-7=3(2+2y)-4y+7 equation: 



7y-7=3(2+2y)-4y+7

We move all terms to the left:

7y-7-(3(2+2y)-4y+7)=0

We add all the numbers together, and all the variables

7y-(3(2y+2)-4y+7)-7=0



We calculate terms in parentheses: -(3(2y+2)-4y+7), so:

3(2y+2)-4y+7

We add all the numbers together, and all the variables

-4y+3(2y+2)+7

We multiply parentheses

-4y+6y+6+7

We add all the numbers together, and all the variables

2y+13

Back to the equation:

-(2y+13)



We get rid of parentheses

7y-2y-13-7=0

We add all the numbers together, and all the variables

5y-20=0

We move all terms containing y to the left, all other terms to the right

5y=20

y=20/5

y=4

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