7y-48=16+3y

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Solution for 7y-48=16+3y equation: 



7y-48=16+3y

We move all terms to the left:

7y-48-(16+3y)=0

We add all the numbers together, and all the variables

7y-(3y+16)-48=0

We get rid of parentheses

7y-3y-16-48=0

We add all the numbers together, and all the variables

4y-64=0

We move all terms containing y to the left, all other terms to the right

4y=64

y=64/4

y=16

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