7y-3=3(y+4)

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Solution for 7y-3=3(y+4) equation: 



7y-3=3(y+4)

We move all terms to the left:

7y-3-(3(y+4))=0



We calculate terms in parentheses: -(3(y+4)), so:

3(y+4)

We multiply parentheses

3y+12

Back to the equation:

-(3y+12)



We get rid of parentheses

7y-3y-12-3=0

We add all the numbers together, and all the variables

4y-15=0

We move all terms containing y to the left, all other terms to the right

4y=15

y=15/4

y=3+3/4

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