7y-35=-7(y-1)

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Solution for 7y-35=-7(y-1) equation: 



7y-35=-7(y-1)

We move all terms to the left:

7y-35-(-7(y-1))=0



We calculate terms in parentheses: -(-7(y-1)), so:

-7(y-1)

We multiply parentheses

-7y+7

Back to the equation:

-(-7y+7)



We get rid of parentheses

7y+7y-7-35=0

We add all the numbers together, and all the variables

14y-42=0

We move all terms containing y to the left, all other terms to the right

14y=42

y=42/14

y=3

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