7y-3+(3y+3)=90

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Solution for 7y-3+(3y+3)=90 equation: 



7y-3+(3y+3)=90

We move all terms to the left:

7y-3+(3y+3)-(90)=0

We add all the numbers together, and all the variables

7y+(3y+3)-93=0

We get rid of parentheses

7y+3y+3-93=0

We add all the numbers together, and all the variables

10y-90=0

We move all terms containing y to the left, all other terms to the right

10y=90

y=90/10

y=9

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