7y-3(y-2)=6(y+1)

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Solution for 7y-3(y-2)=6(y+1) equation: 



7y-3(y-2)=6(y+1)

We move all terms to the left:

7y-3(y-2)-(6(y+1))=0

We multiply parentheses

7y-3y-(6(y+1))+6=0



We calculate terms in parentheses: -(6(y+1)), so:

6(y+1)

We multiply parentheses

6y+6

Back to the equation:

-(6y+6)



We add all the numbers together, and all the variables

4y-(6y+6)+6=0

We get rid of parentheses

4y-6y-6+6=0

We add all the numbers together, and all the variables

-2y=0

y=0/-2

y=0

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