7y+8-2(-3y-2)=3(y-1)

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Solution for 7y+8-2(-3y-2)=3(y-1) equation: 



7y+8-2(-3y-2)=3(y-1)

We move all terms to the left:

7y+8-2(-3y-2)-(3(y-1))=0

We multiply parentheses

7y+6y-(3(y-1))+4+8=0



We calculate terms in parentheses: -(3(y-1)), so:

3(y-1)

We multiply parentheses

3y-3

Back to the equation:

-(3y-3)



We add all the numbers together, and all the variables

13y-(3y-3)+12=0

We get rid of parentheses

13y-3y+3+12=0

We add all the numbers together, and all the variables

10y+15=0

We move all terms containing y to the left, all other terms to the right

10y=-15

y=-15/10

y=-1+1/2

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