7y+8+3y=9-2(-5y-3)-7

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Solution for 7y+8+3y=9-2(-5y-3)-7 equation: 



7y+8+3y=9-2(-5y-3)-7

We move all terms to the left:

7y+8+3y-(9-2(-5y-3)-7)=0

We add all the numbers together, and all the variables

10y-(9-2(-5y-3)-7)+8=0



We calculate terms in parentheses: -(9-2(-5y-3)-7), so:

9-2(-5y-3)-7

determiningTheFunctionDomain
-2(-5y-3)+9-7

We add all the numbers together, and all the variables

-2(-5y-3)+2

We multiply parentheses

10y+6+2

We add all the numbers together, and all the variables

10y+8

Back to the equation:

-(10y+8)



We get rid of parentheses

10y-10y-8+8=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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