7y+5y-27=9(3y-6)+35-5y

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Solution for 7y+5y-27=9(3y-6)+35-5y equation:



7y+5y-27=9(3y-6)+35-5y
We move all terms to the left:
7y+5y-27-(9(3y-6)+35-5y)=0
We add all the numbers together, and all the variables
12y-(9(3y-6)+35-5y)-27=0
We calculate terms in parentheses: -(9(3y-6)+35-5y), so:
9(3y-6)+35-5y
determiningTheFunctionDomain 9(3y-6)-5y+35
We add all the numbers together, and all the variables
-5y+9(3y-6)+35
We multiply parentheses
-5y+27y-54+35
We add all the numbers together, and all the variables
22y-19
Back to the equation:
-(22y-19)
We get rid of parentheses
12y-22y+19-27=0
We add all the numbers together, and all the variables
-10y-8=0
We move all terms containing y to the left, all other terms to the right
-10y=8
y=8/-10
y=-4/5

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