7y+5=4(y-2)+3

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Solution for 7y+5=4(y-2)+3 equation: 



7y+5=4(y-2)+3

We move all terms to the left:

7y+5-(4(y-2)+3)=0



We calculate terms in parentheses: -(4(y-2)+3), so:

4(y-2)+3

We multiply parentheses

4y-8+3

We add all the numbers together, and all the variables

4y-5

Back to the equation:

-(4y-5)



We get rid of parentheses

7y-4y+5+5=0

We add all the numbers together, and all the variables

3y+10=0

We move all terms containing y to the left, all other terms to the right

3y=-10

y=-10/3

y=-3+1/3

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